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used chevrolet s-10 pickups

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Q: Whats a better pickup truck a Chevrolet S-10, Toyota Tacoma, or a Nissan pickup?
I need to buy a used truck for my landscaping business but I don’t know which one would be better?

My friend is selling me his 1995 Chevrolet S-10 pickup truck xtra-cab manual transmission, 4 cylinders, 150k miles for $2,700.00 do you think it’s a good buy?

A: Its all about maintenance. If you take care of it they last. If not they don’t.

If you manage to get 10 mpg in an S10 something is wrong with it.

Q: I have a 1991 Chevrolet S-10 pickup which suddenly stopped running.?
It had sat in my driveway for over a year without being run. After using it for short errands recently over the last week, it died on me. I can start it and it will run as long as my foot is on the gas pedal, but the minute I take my foot off, it dies. Can you tell me what might be wrong? Also, I have replaced the fuel filter and tried to empty the bad gas out of the tank. I can prime it, and it will run for a short period. PLEASE HELP!

A: i couldnt find any thng specific in my haynes but my brain tells me u got a bad sensor. i would guess air idle control valve is high on the list. second would be mass air flow and third would be throttle position sensor. i would go to junk yard and get aicv and toss that in. it will cost next to nothing. if that doesnt do it, bite the bullet and take it in for 85 bucks and have them diagnose it for you. good luck, keep your greasy side down.

Q: Statistics question below…help!?
The June 1997 day’s supply of Chevrolet S-10 pickup trucks was 106 vehicles, but shortly after the United Auto Workers strike in Flint, Michigan, the June 1998 day’s supply of these trucks had dropped to a mean of 38 and a standard deviation of 16 (Newsweek, “Big, Empty Lots,” July 27, 1998). Suppose one month after the strike was settled, 150 dealers are sampled and the S-10 inventories yielded a mean day’s supply of 41 trucks. Based on this new evidence, complete the hypothesis test of : = 38 versus : > 38 at the 0.02 level of significance using the probability-value approach.

Define the parameter
Define the null hypothesis and alternative hypothesis
Specify the hypothesis criteria
Determine the results.

Please help!!! :)

A: Parameter is mean day’s supply of Chevrolet S-10 pickup trucks
H0: μ =38
HA: μ >38
μ = parameter defined above
σ = 16 (standard deviation)
n=150 (number of people sampled)
Find the test statistic z. If this exceeds the critical z-value with 0.02 level of significance, reject the null hypothesis and accept the alternative.
Standard error of mean = sd / sqrt(n)
SE = 16/12.2474
Standard error of mean 1.3064
z = (xbar-μ) /se
z = (41-38) / 1.3064
z = 2.2964
The critical value is 2.05
Compted z exceeds critical z; hence, reject the null hypothesis and conclude that the mean supply has increased.

Q: Statistics HARD question….anyone please help ASAP??
When workers for a auto maker go on strike, there are repercussions through the economy; in particular, dealers who sell the cars feel the pinch. Dealers like to maintain a two-month supply to give their customers selection, but when the manufacturer cant deliver the vehicles, inventories dwindle. The June 1997 day’s supply of Chevrolet S-10 pickup trucks was 106 vehicles, but shortly after the United Auto Workers strike in Michigan, the June 1998 day’s supply of these trucks had dropped to a mean of 38 and a standard deviation of 16. Suppose one month after the strike settled,150 dealers are sampled and the S-10 inventories yielded a mean day’s supply of 41 trucks. Based on new evidence, complete the hypothesis test of Ho: mean= 38 versus Ha:mean > 38 at the 0.02 level of significance using the probability-value approach.
a.)Define the parameter. b.)The null and alt hypothesis c.) Hypothesis criteria d.) Present the sample evidence e.)Prob Distribution info f.) Determine the results

A: We wish to test
Ho: U = 38
versus
Ha: U > 38
to prove whether the population or true mean supply of trucks by the dealers is greater than 38 or not. We wish to reject Ho(the null hypothesis) in favor of Ha(the alternative hypothesis) based on evidence from our sample.

The test static = Z
= (x-bar-U)/(s/√n)
Z = (41-38)/(16/√150)
Z = 2.30

We can only reject HO in favor of Ha if and only if Z>Z∞. Alternatively, We can also reject Ho if the p-value is less than that of our chosen ∞.

At our chosen ∞=0.02 level of significance,
Our chosen rejection point
= Z∞= z0.02 = z(0.5-0.48)
= 2.05

P-value for this hypothesis testing
= Area on the right ended or tailed of the test static z=2.05 under the standard normal curve
= P(z>0) – P(0 = 0.5 – 0.4893
= 0.0107

Since the test static z = 2.30 is greater than that of our chosen rejection point z0.02 = 2.05, then we can reject Ho in favor of Ha at the ∞ = 0.02 significance level, based on data extracted from our new random selected sample. The p -value of 0.0107 is less than z0.02=2.05, which means that we have sufficient evidence to prove that Ha is true and Ho is false. We conclude that the mean day’s supply of trucks by the dealers is indeed true based on our sample evidence.

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